Integrand size = 32, antiderivative size = 116 \[ \int (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {\left (2 a^2 B+b^2 B+2 a b C\right ) \text {arctanh}(\sin (c+d x))}{2 d}+\frac {2 \left (3 a b B+a^2 C+b^2 C\right ) \tan (c+d x)}{3 d}+\frac {b (3 b B+2 a C) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {C (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d} \]
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Time = 0.16 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.156, Rules used = {4141, 4133, 3855, 3852, 8} \[ \int (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {\left (2 a^2 B+2 a b C+b^2 B\right ) \text {arctanh}(\sin (c+d x))}{2 d}+\frac {2 \left (a^2 C+3 a b B+b^2 C\right ) \tan (c+d x)}{3 d}+\frac {b (2 a C+3 b B) \tan (c+d x) \sec (c+d x)}{6 d}+\frac {C \tan (c+d x) (a+b \sec (c+d x))^2}{3 d} \]
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Rule 8
Rule 3852
Rule 3855
Rule 4133
Rule 4141
Rubi steps \begin{align*} \text {integral}& = \frac {C (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac {1}{3} \int (a+b \sec (c+d x)) \left ((3 a B+2 b C) \sec (c+d x)+(3 b B+2 a C) \sec ^2(c+d x)\right ) \, dx \\ & = \frac {b (3 b B+2 a C) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {C (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac {1}{6} \int \left (3 \left (2 a^2 B+b^2 B+2 a b C\right ) \sec (c+d x)+4 \left (3 a b B+a^2 C+b^2 C\right ) \sec ^2(c+d x)\right ) \, dx \\ & = \frac {b (3 b B+2 a C) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {C (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac {1}{2} \left (2 a^2 B+b^2 B+2 a b C\right ) \int \sec (c+d x) \, dx+\frac {1}{3} \left (2 \left (3 a b B+a^2 C+b^2 C\right )\right ) \int \sec ^2(c+d x) \, dx \\ & = \frac {\left (2 a^2 B+b^2 B+2 a b C\right ) \text {arctanh}(\sin (c+d x))}{2 d}+\frac {b (3 b B+2 a C) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {C (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}-\frac {\left (2 \left (3 a b B+a^2 C+b^2 C\right )\right ) \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{3 d} \\ & = \frac {\left (2 a^2 B+b^2 B+2 a b C\right ) \text {arctanh}(\sin (c+d x))}{2 d}+\frac {2 \left (3 a b B+a^2 C+b^2 C\right ) \tan (c+d x)}{3 d}+\frac {b (3 b B+2 a C) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {C (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d} \\ \end{align*}
Time = 0.36 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.79 \[ \int (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {3 \left (2 a^2 B+b^2 B+2 a b C\right ) \text {arctanh}(\sin (c+d x))+\tan (c+d x) \left (3 b (b B+2 a C) \sec (c+d x)+2 \left (6 a b B+3 a^2 C+3 b^2 C+b^2 C \tan ^2(c+d x)\right )\right )}{6 d} \]
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Time = 0.80 (sec) , antiderivative size = 118, normalized size of antiderivative = 1.02
method | result | size |
parts | \(\frac {\left (B \,b^{2}+2 C a b \right ) \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}+\frac {\left (2 B a b +C \,a^{2}\right ) \tan \left (d x +c \right )}{d}+\frac {B \,a^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}-\frac {C \,b^{2} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )}{d}\) | \(118\) |
derivativedivides | \(\frac {B \,a^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+C \,a^{2} \tan \left (d x +c \right )+2 B \tan \left (d x +c \right ) a b +2 C a b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+B \,b^{2} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-C \,b^{2} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )}{d}\) | \(143\) |
default | \(\frac {B \,a^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+C \,a^{2} \tan \left (d x +c \right )+2 B \tan \left (d x +c \right ) a b +2 C a b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+B \,b^{2} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-C \,b^{2} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )}{d}\) | \(143\) |
parallelrisch | \(\frac {-9 \left (B \,a^{2}+\frac {1}{2} B \,b^{2}+C a b \right ) \left (\frac {\cos \left (3 d x +3 c \right )}{3}+\cos \left (d x +c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+9 \left (B \,a^{2}+\frac {1}{2} B \,b^{2}+C a b \right ) \left (\frac {\cos \left (3 d x +3 c \right )}{3}+\cos \left (d x +c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (6 B a b +3 C \,a^{2}+2 C \,b^{2}\right ) \sin \left (3 d x +3 c \right )+3 \left (B \,b^{2}+2 C a b \right ) \sin \left (2 d x +2 c \right )+6 \left (B a b +\frac {1}{2} C \,a^{2}+C \,b^{2}\right ) \sin \left (d x +c \right )}{3 d \left (\cos \left (3 d x +3 c \right )+3 \cos \left (d x +c \right )\right )}\) | \(197\) |
norman | \(\frac {\frac {4 \left (6 B a b +3 C \,a^{2}+C \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 d}-\frac {\left (4 B a b -B \,b^{2}+2 C \,a^{2}-2 C a b +2 C \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{d}-\frac {\left (4 B a b +B \,b^{2}+2 C \,a^{2}+2 C a b +2 C \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{3}}-\frac {\left (2 B \,a^{2}+B \,b^{2}+2 C a b \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{2 d}+\frac {\left (2 B \,a^{2}+B \,b^{2}+2 C a b \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{2 d}\) | \(207\) |
risch | \(-\frac {i \left (3 B \,b^{2} {\mathrm e}^{5 i \left (d x +c \right )}+6 C a b \,{\mathrm e}^{5 i \left (d x +c \right )}-12 B a b \,{\mathrm e}^{4 i \left (d x +c \right )}-6 C \,a^{2} {\mathrm e}^{4 i \left (d x +c \right )}-24 B a b \,{\mathrm e}^{2 i \left (d x +c \right )}-12 C \,a^{2} {\mathrm e}^{2 i \left (d x +c \right )}-12 C \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-3 B \,b^{2} {\mathrm e}^{i \left (d x +c \right )}-6 C b a \,{\mathrm e}^{i \left (d x +c \right )}-12 B a b -6 C \,a^{2}-4 C \,b^{2}\right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{3}}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B \,a^{2}}{d}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B \,b^{2}}{2 d}-\frac {a b \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) C}{d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B \,a^{2}}{d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B \,b^{2}}{2 d}+\frac {a b \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) C}{d}\) | \(298\) |
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Time = 0.27 (sec) , antiderivative size = 150, normalized size of antiderivative = 1.29 \[ \int (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {3 \, {\left (2 \, B a^{2} + 2 \, C a b + B b^{2}\right )} \cos \left (d x + c\right )^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, {\left (2 \, B a^{2} + 2 \, C a b + B b^{2}\right )} \cos \left (d x + c\right )^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (2 \, C b^{2} + 2 \, {\left (3 \, C a^{2} + 6 \, B a b + 2 \, C b^{2}\right )} \cos \left (d x + c\right )^{2} + 3 \, {\left (2 \, C a b + B b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{12 \, d \cos \left (d x + c\right )^{3}} \]
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\[ \int (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\int \left (B + C \sec {\left (c + d x \right )}\right ) \left (a + b \sec {\left (c + d x \right )}\right )^{2} \sec {\left (c + d x \right )}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.42 \[ \int (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {4 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C b^{2} - 6 \, C a b {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 3 \, B b^{2} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 12 \, B a^{2} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 12 \, C a^{2} \tan \left (d x + c\right ) + 24 \, B a b \tan \left (d x + c\right )}{12 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 294 vs. \(2 (108) = 216\).
Time = 0.35 (sec) , antiderivative size = 294, normalized size of antiderivative = 2.53 \[ \int (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {3 \, {\left (2 \, B a^{2} + 2 \, C a b + B b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 3 \, {\left (2 \, B a^{2} + 2 \, C a b + B b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {2 \, {\left (6 \, C a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 12 \, B a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 6 \, C a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 3 \, B b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 6 \, C b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 12 \, C a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 24 \, B a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 4 \, C b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 6 \, C a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 12 \, B a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 6 \, C a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, B b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 6 \, C b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{3}}}{6 \, d} \]
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Time = 20.64 (sec) , antiderivative size = 227, normalized size of antiderivative = 1.96 \[ \int (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {\mathrm {atanh}\left (\frac {4\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (B\,a^2+C\,a\,b+\frac {B\,b^2}{2}\right )}{4\,B\,a^2+4\,C\,a\,b+2\,B\,b^2}\right )\,\left (2\,B\,a^2+2\,C\,a\,b+B\,b^2\right )}{d}-\frac {\left (2\,C\,a^2-B\,b^2+2\,C\,b^2+4\,B\,a\,b-2\,C\,a\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (-4\,C\,a^2-8\,B\,a\,b-\frac {4\,C\,b^2}{3}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (B\,b^2+2\,C\,a^2+2\,C\,b^2+4\,B\,a\,b+2\,C\,a\,b\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6-3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-1\right )} \]
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